Two of the terms involve \(x\) and two involve \(y\). Now we can combine the \(x\) terms and combine the \(y\) terms to get \(3x + 2y\).

Simplify \(\frac{3t + 6}{3t}\). The numerator of this fraction will factorise as there is a common factor of 3. This gives \(\frac{3(t + 2)}{3t}\). Now, there is clearly a common factor of 3 between ...